If $\sum_{r=1}^{n}r^3 - \sum_{p=1}^{n} \sum_{m=1}^{p} \sum_{r=1}^{m} 1 = 80$,then the possible value of $n$ is:

  • A
    $3$
  • B
    $4$
  • C
    $5$
  • D
    $6$

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